X+(2x+1)^(1/2)=7

Solution for X+(2x+1)^(1/2)=7 equation:

X+(2X+1)^(1/2)=7

We move all terms to the left:

X+(2X+1)^(1/2)-(7)=0

We add all the numbers together, and all the variables

X+(2X+1)^(+1/2)-7=0

We multiply all the terms by the denominator


X*2)+(2X+1+1)^(-7*2)=0

We add all the numbers together, and all the variables

X*2)+(2X+2)^(-14)=0

We add all the numbers together, and all the variables

X*2)+(2X=0

Wy multiply elements

2X^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$X=\frac{-b}{2a}=\frac{0}{4}=0$